the common difference & 13th term of A.P -0.8,-0.675,-0.55 is
Answers
Answer:
The objective of this study was to investigate pretreatment systemic inflammatory response (SIR) markers in patients who underwent initial intravesical treatment for high-risk non-muscle invasive bladder cancer (NMIBC). A total of 385 patients who underwent initial intravesical Bacillus Calmette-Guerin treatment after transurethral resection of bladder tumor (TURB) were included. We analyzed the relationship between oncological outcomes and ratios of SIR markers, including neutrophil-to-lymphocyte ratio (NLR), derived neutrophil-to-lymphocyte ratio (dNLR), and platelet-to-lymphocyte ratio (PLR). Each SIR marker was used for analysis. Their cut-off values were determined through receiver operation characteristics curves analysis. Patients were divided into two groups according to pretreatment NLR (<1.5 vs. ≥1.5), dNLR (<1.2 vs. ≥1.2), and PLR values (171< vs. ≥171). Patients with NLR ≥ 1.5 and dNLR ≥ 1.2 were associated with poor prognosis in terms of overall survival and cause-specific survival. However, no serum SIR marker was associated with prognosis in recurrence-free survival or progression-free survival. Cox multivariate analysis revealed that age, NLR, dNLR, hemoglobin, and pathologic T stage were significant factors predicting overall survival. Age, NLR, and pathologic T stage were significant factors predicting cancer-specific survival, NLR and tumor number were the most important predictors of bladder preserving survival. NLR before treatment was correlated with both oncological outcomes and survival outcome in NMIBC patients undergoing initial intravesical B CG treatment after TURB. Increased NLR reflects a poor prognosis of these outcomes.
Keywords: BCG, bladder cancer, neutrophil-to-lymphocyte ratio, systemic inflammatory response, non-muscle invasive bladder cancer
Step-by-step explanation:
common difference = 0.125
13th term = 0.7
Step-by-step explanation:
common difference = -0.55 - ( -0.675 )
= .675 - .55
= 0.125
first term (a) = - 0.8
13 th term
Tn = a + (n-1) d
= -0.8 + (12)*0.125
= 0.7