Question

The common difference of an anthmetic sequence is
1 and the product of the first and the third terms is
143. What are the first three terms?​

Answer 1

Step-by-step explanation:

Let first term be (a-d), a, (a+d)

(a-d) (a+d)=143

since d=1

(a-1) (a+1)=a^2-1=143

a^2=144

a=+12 or -12

if a=+12 then AP=11,12,13

if a= -12 then AP= -13,-12,-11

go for it dude.....