Question

the common difference of an ap whose sum of n terms is Sn​

Answer 1

HOPE IT HELP YOU MY FRIEND

Answer 2

Step-by-step explanation:

Sum of AP, Sn =

$\frac{n}{2} (2a + (n - 1)d)$

Now,

$2 s_{n} = 2an + ({n}^{2} - n)d \\ 2 s_{n} - 2an = ({n}^{2} - n)d \\ \frac{2 s_{n} - 2an}{ ({n}^{2} - n)} = d$