Math, asked by minatisatapathy1972, 1 year ago

The common difference of an arithmetic progression in which a15 -a6 =-27/2 ,is ( where an is the nth term of the given AP)

Answers

Answered by ishoo33
1
hay hii....the ans is -3/2
Answered by virtuematane
2

Answer:

The common difference of an arithmetic progression is: \dfrac{-3}{2}

Step-by-step explanation:

The nth term in an A.P. is given by:

a_{n}=a+(n-1)d

where a is the first term of an A.P. and d is the common difference in an A.P.

We are given :

a_{15}-a_{6}=\dfrac{-27}{2}\\ \\a+(15-1)d-(a+(6-1)d)=\dfrac{-27}{2}\\\\a+14d-(a+5d)=\dfrac{-27}{2}\\\\a+14d-a-5d=\dfrac{-27}{2}\\\\9d=\dfrac{-27}{2}\\\\d=\dfrac{-3}{2}

Hence, the common difference of an arithmetic progression is: \dfrac{-3}{2}


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