Question

the common difference of an arithmetic sequence is -3 and the square of the fifth term is equal to the first term of an arithmetic sequence​

Answer 1

Answer:

Step-by-step explanation:

common difference(d)= -3

According to question

${a_{5} }^2= a_{1}$

$a_{5}$=(a+4d)    

$a_{1}$=a

therfore    

a+4d=a                       d= -3 (given)

a+4*-3 = a

a-12=a

a+a=12

2a= 12

a= 6

hence u can find all the values of AP by using the formula

$t_{n} =a+(n-1)d$    

where n=number of terms

d = common difference

a=first term of the AP

thank u.........have a nice day