The common difference of an arithmetic sequence is 6 and its ninth term is is zero what is the 8th and 10th time and what is the sum of of first 17 terms
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T9 = 0
a + 8d = 0
a + 8(6) = 10
a + 48 = 0
a = -48
T8 = a + 7d
-48 + 7(6) = -6
T10 = a + 9d
= -48 + 9(6)
= 6
s17 = n/2 {2a + (n-1) d}
17/2 {2(-48) + 16(6) }
8.5(-96 + 96)
8.5(0) = 0
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