The common difference of of an AP is -2 find its sum if it dirst term is 100 and last term is - p
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Step-by-step explanation:
d = -2, a = 100, Tn = -p
Sn = n/2 [2a+(n-1)d]
Sn = -p/2{2×100+[(-p)-1)(-2)]}
Sn = -p/2{200+(2p+2)}
Sn = -p/2{2[100+p+1]}
Sn = -p/2×2[101+p]
Sn = -p(101+p)
Sn = -101p-p^2
Sn = p^2-101
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