The common difference of two ap are equal. The 1st term of an ap is 3 more than the 1st term of second ap. if the 7th term of ap is 28 and 8th term of second ap is 29 , then find both .
Answers
Answer:
First AP: 4, 8, 12, 16. . . . .
Second AP: 1, 5, 9, 13. . . . .
Step-by-step explanation:
Given that:
The common difference of two AP are equal.
To Find:
Both the AP.
We know that:
aₙ = a + (n - 1)d
Where,
aₙ = nth term
a = First term
n = Number of terms
d = Common difference
Let us assume:
Common difference be d.
First term of first AP be a.
First term of second AP be A.
The 1st term of an AP is 3 more than the 1st term of second AP:
⇢ a = A + 3 _____(i)
The 7th term of AP is 28:
⇢ a₇ = 28
⇢ a + (7 - 1)d = 28
⇢ a + 6d = 28
Substituting the value of a from eqⁿ(i).
⇢ A + 3 + 6d = 28
⇢ A = 28 - 3 - 6d
⇢ A = 25 - 6d _____(ii)
8th term of second AP is 29:
⇢ A₈ = 29
⇢ A + (8 - 1)d = 29
⇢ A + 7d = 29
Substituting the value of A from eqⁿ(ii).
⇢ 25 - 6d + 7d = 29
⇢ 25 + d = 29
⇢ d = 29 - 25
⇢ d = 4
In equation (ii).
⇢ A = 25 - 6d
Putting the value of d.
⇢ A = 25 - 6(4)
⇢ A = 25 - 24
⇢ A = 1
In equation (i)
⇢ a = A + 3
Putting the value of A.
⇢ a = 1 + 3
⇢ a = 4
Finding first AP:
Common difference = d = 4
First term of first AP = a = 4
Second term = a + d = 4 + 4 = 8
Third term = a + 2d = 4 + 2(4) = 12
Fourth term = a + 3d = 4 + 3(4) = 16
∴ First AP: 4, 8, 12, 16. . . . .
Finding second AP:
Common difference = d = 4
First term of second AP = 1
Second term = a + d = 1 + 4 = 5
Third term = a + 2d = 1 + 2(4) = 9
Fourth term = a + 3d = 1 + 3(4) = 13
∴ Second AP: 1, 5, 9, 13. . . . .
Answer:
First AP: 4, 8, 12, 16. . . . .
Second AP: 1, 5, 9, 13. . . . .
Step-by-step explanation:
Given that:
The common difference of two AP are equal.
To Find:
Both the AP.
We know that:
aₙ = a + (n - 1)d
Where,
aₙ = nth term
a = First term
n = Number of terms
d = Common difference
Let us assume:
Common difference be d.
First term of first AP be a.
First term of second AP be A.
The 1st term of an AP is 3 more than the 1st term of second AP:
⇢ a = A + 3 _____(i)
The 7th term of AP is 28:
⇢ a₇ = 28
⇢ a + (7 - 1)d = 28
⇢ a + 6d = 28
Substituting the value of a from eqⁿ(i).
⇢ A + 3 + 6d = 28
⇢ A = 28 - 3 - 6d
⇢ A = 25 - 6d _____(ii)
8th term of second AP is 29:
⇢ A₈ = 29
⇢ A + (8 - 1)d = 29
⇢ A + 7d = 29
Substituting the value of A from eqⁿ(ii).
⇢ 25 - 6d + 7d = 29
⇢ 25 + d = 29
⇢ d = 29 - 25
⇢ d = 4
In equation (ii).
⇢ A = 25 - 6d
Putting the value of d.
⇢ A = 25 - 6(4)
⇢ A = 25 - 24
⇢ A = 1
In equation (i)
⇢ a = A + 3
Putting the value of A.
⇢ a = 1 + 3
⇢ a = 4
Finding first AP:
Common difference = d = 4
First term of first AP = a = 4
Second term = a + d = 4 + 4 = 8
Third term = a + 2d = 4 + 2(4) = 12
Fourth term = a + 3d = 4 + 3(4) = 16
∴ First AP: 4, 8, 12, 16. . . . .
Finding second AP:
Common difference = d = 4
First term of second AP = 1
Second term = a + d = 1 + 4 = 5
Third term = a + 2d = 1 + 2(4) = 9
Fourth term = a + 3d = 1 + 3(4) = 13
∴ Second AP: 1, 5, 9, 13. . . . .