Question

The common difference of two different ap are equal the first term of first ap is 3 more than the first term of second a.p if the 7th term of first ap is 28and 8th term of 2nd ap is 29. Then find two aps​

Answer 1

Answer:

heya here you go

Step-by-step explanation:

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Answer 2

Answer:

Required the first AP is {4, 8, 12, 16, ...} and the second AP is {1, 5, 9, 13, ...

Step-by-step explanation:

Let the first AP be {a, a+d, a+2d, a+3d, ...} and the second AP be {b, b+d, b+2d, b+3d, ...} where d is the common difference of both APs.

Given that d is common to both APs and a = b + 3.

Also, the 7th term of the first AP is 28, so we have:

$a + 6d = 28 \\ (b + 3) + 6d = 28 \\ b + 6d = 25$

Similarly, the 8th term of the second AP is 29, so we have:

b + 7d = 29

We now have two equations in two variables (b and d):

b + 6d = 25

b + 7d = 29

Subtracting the first equation from the second, we get:

d = 4

Substituting d = 4 in the first equation, we get:

b = 1

So, the first AP is {4, 8, 12, 16, ...} and the second AP is {1, 5, 9, 13, ...}.

Know more about Arithmetic progression:

1) https://brainly.in/question/4219484

2) https://brainly.in/question/2768711

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