Math, asked by Tanishhsuryavanshi, 1 year ago

The common factor of 16a_bc - 12ab²c + 20a2b2c2 is _

Answers

Answered by pawankanaujiya58

3

Step-by-step explanation:

16abc-12ab^2c+20(abc)^2

=4abc(4-3b+5abc)

common factor is 4abc

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