The common ratio of a geometric sequence is 3/2. Find the first three terms if the fifth term is 1.
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Answer:
16/81, 8/27,and 4/9
Step-by-step explanation:
Given
Common ratio r = 3/2
Let the first term be 'a'.
Fifth term = a₅ = 1
We know that
For the nth term in G.P with common ratio 'r' and the first term 'a' is
aₙ = arⁿ⁻¹
⇒a₅= 1
⇒ar⁵⁻¹ = 1
⇒ar⁴ = 1
⇒a(3/2)⁴ = 1
⇒a = 1 / (3/2)⁴
⇒a = 2⁴/3⁴ = 16/81
∴a = 16/81
The first three terms of G.P are a, ar and ar².
∴ a₁ = a =16/81
a₂ = ar = (16/81)*(3/2) = 8/27
a₃ = ar² = (16/81)*(3/2)² = (16/81)* (9/4) = 4/9
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