Question

the common ratio of a GP having 10th term and 1st term equal to 1536 and -3 is??
pls snd me full solution​

Answer 1

Answer:

Common ratio -2

Step-by-step explanation:

10th tetm is 1536

1st term is -3

a = -3

$ar ^{10 - 1} = 1536 \\ - 3r ^{9} = 1536 \\ r^{9} = 1536 \div ( - 3) \\ {r}^{9} = - 512 \\ r \: = - 2$