Math, asked by apple2223, 10 months ago

the common root of x2-5x+6=0 and x2-x-2=0​

Answers

Answered by puja7186
0

2. x^2_x_2

x^2_2x+x_2

x(x_2)+1(x_2).

(x_2)(x+1).

Answered by iTzMiSsTwinKle
1

Answer:

=common root in both the eqn is 2

Step-by-step explanation:

 {x}^{2}  - 5x + 6 = 0 \\ middle \: term \: splitting \\  {x}^{2}  - 2x - 3x + 6 = 0 \\ x(x - 2) - 3(x - 2) = 0 \\( x - 3)(x - 2) = 0 \\ x = 3 \: and \: 2 \\  second \: eqn \\ {x}^{2}  - x - 2 = 0 \\ d =  {b}^{2}  - 4ac \\  \:  \:   \: =  ({ - 1})^{2}   + 8 \\   \:  \:  \: = 1 + 8 = 9 \\ x =  \frac{ - b +  \sqrt{d} }{2  \times a } \:  \:  \:  \:  \:  \:   \:  \:  \:  \:\frac{ - b  - \sqrt{d} }{2  \times a }   \\  \:  \:  \:   \:=  \frac{1 + 3}{2}  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \frac{1  - 3}{2} \\  \:   \:  \:  =  \frac{4}{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \frac{ - 2}{2}  \\ x = 2 \: and \:  - 1 \\ common \: roots \: between \: both \: the \: eqn \: are \:  \\  = 2 \\ so \: answer \: is \: 2

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