Math, asked by santhrupthraomssalan, 2 months ago

the complementary function of (D^2-16) y=0 is​

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Answered by gundubillipravallika
0

Step-by-step explanation:

hope this answer may help you get the point

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Answered by mithun890
0

Answer: 4

(D^{2}-16 )y=0

Now consider the symbolic form

D^{2} -16=0

D^{2} =16

D= +4

   =+4or-4

y_{c} =C_{1} e^{4x} +C_{2} e^{-4x}

∴ it is an complementary function.

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