The complete solution of 7cos^2x + sinxcosx - 3 = 0 is ?
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Answer:
The given equation is equivalent to
7cos
2
x+sinxcosx−3(sin
2
x+cos
2
x)=0
or 3sin
2
x−sinxcosx−4cos
2
x=0
Since cosx=0 does not satisfy the given equation .
Divide throughout by cos
2
x we get
3tan
2
x−tanx−4=0
⇒(3tanx−4)(tanx+1)=0
⇒tanx=
3
4
or tanx=−1
x=kπ+tan
−1
3
4
or x=nπ+
4
3π
(n,k∈I)
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