Question

The complete solution set of log2(x + 1) < log2 (x2 + 6x + 7) is
(1) x (1, 0)
(2) x + (-2, …)
(3) x (-3, )
4 x 6 (-1, …)
TL​

Answer 1

Step-by-step explanation:

Refer to attachment

Hope it helps :-)

Answer 2

Answer:

3

Step-by-step explanation:

log2(X+1)<log2(x^2+6x+7)

divide log2 by both

X+1<(x^2+6x+7)

0< x^2+5x+6

0< x^2+3x+2x+6

0< x(X+3)+2(X+3)

X>-3: X>-2

therefore and is 3