the complex ion cu(nh3)4 2+ the geometry will be
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Explanation:
To Find -
- Geometry of [Cu(NH₃)₄]²⁺
Solution -
O.N. of Cu in [Cu(NH₃)₄]²⁺ is
x + 0×4 = 2
x = +2
Electronic configuration of Cu -
- ₂₉Cu = ₁₈[Ar] 4s¹ 3d¹⁰
Then,
Electronic configuration of Cu²⁺ -
- Cu²⁺ = ₁₈[Ar] 3d⁹
Then,
Orbital diagram =
(Refer to the attachment)
C.N. = Ligan × Denticity
4 × 1
= 4
Hence,
Hybridisation = sp³ (Tetrahedral)
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[Cu(NH3)4]2+ + is a tetrahedral complex and is therefore non-centrosymmetric.
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