The complex with highest number of unpaired electrons is
A) K4[Fe(CN)6] B) K4[FeF6]
C) [Ti(H O) ]
3+
D) [Cr(NH ) ]
3+
2 6 3 6
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Answered by
4
Explanation:
In [CuBr41]2−, the Cu2+(3d9) atom undergoes sp3 hybridization and contains 1 unpaired electrons. hence, it has maximum number of unpaired electrons.
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3
Answer:
I hope question this one
Explanation:
if it is the question ... I have written the electronic configuration near it ....
hope u understand ...
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