Question

the component along y-axis is half of the maximum value, for angle theta =
a.0°
b.30°
c.60°
d.90°

​

Answer 1

Answer:

a.0° is answer dear friends

Answer 2

Answer:

The component along the y-axis is half of the maximum vector, for angle is $theta=60^{0}$ .

Explanation:

Let the vector be $\vec{A}$$\vec{A}$

Let the angle made by this vector with $y - axis be \theta .$

The component of $\vec{A}$ along $y- axis =A \cos \theta$

For maximum value, $\cos \theta=1$

Maximum value $=A \times 1$

Maximum value$=\mathrm{A}$

So, half of the maximum value $=\frac{A}{2}$

$\Rightarrow A \cos \theta=\frac{A}{2}$

$\Rightarrow \cos \theta=\frac{1}{2}$

$\Rightarrow \theta=60^{0}$

Hence, option (C) is correct.