Question

The component of A =2i+3j along i+j Is

Answer 1

Answer: (10/$\sqrt{26}$)i +(15/$\sqrt{26}$)j

Explanation:

let B = i + j

Cosx = A*B/|A||B| = 5/$\sqrt{26}$

now component of A = Acosx = (5/$\sqrt{26}$)*(2i+3j) = (10/$\sqrt{26}$)i + (15/$\sqrt{26}$)j

Answer 2

Explanation:

it is simply that it has 2 units along the x-axis and 3 units along the y-axis and 2i is itself the component along the x-axis and 3j is the component along the y-axis.