The component of along A vector along B vector is root 3 times that of the component of B vector along A. Then A:B is
a. 1:root3
b. root3:1
c. 2:root3
d. root3:2
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Answer:
according to the question,Acos(theta)=(3)^1/2Bcos(theta)
so A=(3)^1/2B
A:B=(3)^1/2:1
hope it helps
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