Physics, asked by boppishettyvenkatesh, 8 months ago

The component of along A vector along B vector is root 3 times that of the component of B vector along A. Then A:B is
a. 1:root3
b. root3:1
c. 2:root3
d. root3:2

Answers

Answered by anjalikl
9

Answer:

according to the question,Acos(theta)=(3)^1/2Bcos(theta)

so A=(3)^1/2B

A:B=(3)^1/2:1

hope it helps

please mark me as the brainliest.

Similar questions