Question

The component of force vector F​​​​​​1 = 2i^ + 2j^ along force vector F2 = 3j^ + 4k^ is?

Answer 1

Explanation:

F₁  =  2i  +  2j

F₂  =  3j  +  4k

∴ Formula Required for this question is :-

F₁  .  F₂  =  F₁ F₂  cos∅

∴ Component of F₁  along F₂  =  F₁ cos∅

∴  F₁ cos∅  =  ( F₁ . F₂ ) /  F₂

∴  F₁ cos∅  =  ( 2×0  +  2×3  + 0×4 ) /  ( √(3²  +  4²) )

=   6 /  5

∴ Component of F₁ along F₂  =  6 / 5

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Answer 2

Adarsh sacha

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