Question

the component of vector 6i-3j-6k parallel to vector 2j-k is
a) 0
b)-√3
c) 7i-2j-5k
d) -i-j-k​

Answer 1

Answer:a)

Explanation:let a = 6i-3j-6k

and b=2j-k

let a = u +v where u is vector parallel to b and v is perpendicular to b

u = p b where p is constant

v= 6i +(-3-2p)j +(-6+p)

since v dot b = 0

2(-3-2p) -1(-6+p) =0

-6-4p+6-p=0

p= 0

u =0