The component of vector A=axi+ayj+azk along the direction of i−j is ?
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Answered by
5
Correct option is
C
(a
x
−a
y
)/
2
Let two vectors
a
and
b
, then component of vector
a
along the direction of vector
b
is given as
∣
b
∣
a
.
b
,
⇒
2
(a
x
i
+a
y
j
+a
z
k
).(
i
−
j
)
=
2
(a
x
−a
y
)
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