Physics, asked by kosanam, 11 months ago

The components of a force of 100N acting at an angle of 30 with the X-axis is

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Answered by TPS
2
Magnitude of force, F = 100 N

angle with x axis, t = 30°

x component of force = F cos t = 100× cos(30) = 100 × √3/2 = 50√3 N

y component of force = F sin t = 100× sin(30) = 100 × 1/2 = 50 N

F = (50√3 i + 50 j) N
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