Question

The components of a vector A=2i-3j along the vector i+j ?
a)5
b)5/√2
c) 10√2
d) -1/√2​

Answer 1

Explanation:

vetor A along vector B =|A||B|cos theta

vetor(A.B)/|B|=|A|cos theta

2i-3j.i+j/√2= "

5/√2. (B)