Question

The components of the sum of two vectors 2i +3j and
2j + 3k along x and y directions respectively are
[J & K CET 2010)
(a) 2 and 5
(b) 4 and 6
(c) 2 and 6
(d) 4 and 3​

Answer 1

Answer:

in a plane x is equal to i and y is equal to j

Explanation:

so magnitude of that is 2(2) and 3(3) so, 4 and 6

Answer 2

Answer:

The component in $x$ directions is $2$.

The component in $y$ directions is $5$.

Explanation:

We have been given vectors: $2i + 3j$ &  $2j + 3k$

Sum of these vectors will be:

$(2i+3j)+(2j+3k)=2i+(3+2)j+3k =2i+5j+3k$

Therefore,

The component along the $x$-direction & components along the $y$-direction is: $2$units and $5$units respectively.