Question

The % composition of a substance is P =32.63 , 0 =16.82 & S = 50.55. The V.D of substance is 190. Find the molecular formula of the substance .

Answer 1

Your answer:

Find the ratio between the molar mass and the percentage of each element

P = $\frac{32.63}{31}$ = 1

O = $\frac{16.82}{16}$ = 1

S = $\frac{50.55}{32}$ = 1.5

By taking ratio: 1: 1: 1.5 = 2: 2: 3

So, the empirical formula will be: P₂O₂S₃

Molar mass of P₂O₂S₃ = 190

Molar mass of a compound = 2 x V.D

= 2 x 190 = 380

divide 380 by 190

You will get 2

Now, multiply the number of atoms in P₂O₂S₃ by 2

=> P₄O₄S₆ is your answer

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