the % composition of P in Na2HPO4 is (At mass- Na=23 H = 1 p= 31 O= 16
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Answer:
21.83%
Explanation:
the mopecular mass of Na2HPO4= (2×23) + 1 + 31 + (4×16) = 142
The molecular mass of P= 31
Thus the composition of P in Na2HPO4= (31/142) × 100 = 21.8309%
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