The compound A has the percentage composition by following mass: Carbon 26.7%, Oxygen = 71.1%, Hydrogen = 2.2%. Determine the empirical and molecular formula of A, if its vapour density is 45.
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Explanation:
element %. relative no. simplest ratio
H. 2.2. 2.2/1=2.2. 2.2/2.2=1
O. 71.1. 71.1/16=4.4. 4.4/2.2=2
C. 26.7. 26.7/12=2.2. 2.2/2.2=1
empirical formula of compound is CHO2
empirical mass of component=atomic mass of C+atomic mass of H+2x atomic mass of O
=12+1+2×16=45
molecular mass=2×vapour density=2×45=90
n=molecular mass/empirical mass=90/45=2
the molecular formula of compound is C2H2O4
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Answer:
the above answer is correct
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