The compound
CH₃
|
CH₃ — C = CH — CH₃
on reaction with NaIO₄ in the presence of KMnO₄ gives
(a) CH₃CHO + CO₂
(b) CH₃COCH₃
(c) CH₃COCH₃ + CH₃COOH
(d) CH₃COCH₃ + CH₃CHO
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Answer:
(c) CH₃COCH₃ + CH₃COOH
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The compound
CH₃
|
CH₃ — C = CH — CH₃
on reaction with NaIO₄ in the presence of KMnO₄ gives :
•Compound given is isopentylene
• In above reaction, Isopentylene undergoes oxidation to form acetone and acetic acid on reacting with NaIO₄ in presence of KMnO₄.
• Hence correct option is :
(c) CH₃COCH₃ + CH₃COOH
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