The Compound Interest calculated
on a certain Sum of money for the second year is Rs.770 and for the
third year it is Rs.847. Calculate the rate of interest and the Sum
of money.
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Answer:
∵ Difference between the C.I of two successive years=Rs.880−968=Rs.88
∴Rate of interest=
P×T
100×I
=
880×1
100×88
=10%
Let the sum of money=Rs.100
∴interest for one year=10% of 100=
100
10
×100=Rs.10
Amount after one year=100+10=Rs.110
∴Interest foe second year=10% of 110=
100
10
×110=Rs.11
When the interest for second year is rs .11 then sum=Rs.100
When the interest for second year is Rs.880 then sum=
11
100
×880=Rs.8000
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