The compound interest, calculated yearly on a certain sum of money for the 2nd year is Rs 880 & for the 3rd year it is Rs 968. Calculate the rate of interest & the original money.
Answers
Answer:
∵ Difference between the C.I of two successive years=Rs.880−968=Rs.88
∴Rate of interest=
P×T
100×I
=
880×1
100×88
=10%
Let the sum of money=Rs.100
∴interest for one year=10% of 100=
100
10
×100=Rs.10
Amount after one year=100+10=Rs.110
∴Interest foe second year=10% of 110=
100
10
×110=Rs.11
When the interest for second year is rs .11 then sum=Rs.100
When the interest for second year is Rs.880 then sum=
11
100
×880=Rs.8000
Explanation:
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- Compound Interest for 2nd year = Rs. 880
- Compound Interest for 3rd year = Rs. 968
Rate of interest and the original money.
∴ S.I. on Rs. 880 for one year = Rs. 968 - Rs. 880 = Rs. 88
As we know that,
Now, Substituting values in above formula -
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
Lets the original money be Rs. P
✠ C.I. for second year = Amount after 2 years - Amount after 1 year
∴ The rate of interest = 10% and,
∴ The original money = Rs. 8000.