Math, asked by rimadas9831265232, 11 months ago

The compound interest (com-
pounded annually) on Rs.
4200 for 2 years at the rate of
'R' p.c.p.a. is Rs. 882. What
would be the simple interest on
Rs. 5400 for 3 years at the rate
of 'R-3 p.c.p.a.?​

Answers

Answered by puspanjalipatra360
1

Answer:CI=40,501,608, SI=1,732,376

Step-by-step explanation:CI

1: 4200{1+882/100}^2

2:4200*982*982=40,501,608

SI

1:5400*3*1/100=152

2:5400+152=5552

3:5552*3*1=166.56

4:5552+166.56=5718.56

5:5718.56*3*1/100=17,155,68

6:152+166.56+17,155,68=1732376

Answered by Chuchushibi
2

Answer: Rs.1,134

Step-by-step explanation:

As per question,

C.I = 4200{[1+(R/100)^2]-1}

882/4200 = [(100+R)^2 - 10000]/10000

508200/42 = (100+R)^2

=》(100+R)^2 = 12100 = (110)^2

.•. 100+R = 110

R = 10%

.•. S.I = [5400×(10-3)×3] / 100

= 54×7×3

= Rs.1,134

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