Question

The compound interest for ₹ 200 for 2 years at the rate of 10 p. c. p. a is ₹_______ ​

Answer 1

Answer:

42

Step-by-step explanation:

compound interest = P (1+ R/100)^n - P

P= 200 , R = 10 n= 2

so 200( 1+ 10/100)^2

200(110/100)²

200*110/100*110/100

so zeros get cancelled in 200 and 110

we get 2*11*11

= 242- 200

= 42