Math, asked by brijeshkhajuria55, 2 months ago

the compound interest for 2nd year on ₹15000 invested for 3 years at 8%per annum . ​

Answers

Answered by itzbrainlycommando13
0

Simple Interest I=100PNR

Here for first year, 

P=Rs.15,000

N=1 year

R=6 % 

So, Interest at the end of 1st year I=10015,000×1×6=Rs.

.900

And for second year, 

P=Rs.15,000+Rs.900=Rs.15,900

N=1 year

R=6 % 

I=10015,900×1×6=Rs.954

Answered by jaswasri2006
0

for second year,

P=Rs.15,000+Rs.900=Rs.15,900

N=1 year

R=6 %

I = 15,900*1*6/100 = ₹ 954

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