Question

The compound interest for Rs. 200 for 2 year at the rate of 10p.c.p.a. is Rs. ___________ *​

Answer 1

Answer:

• RS 42 /-

Step-by-step explanation:

Given

• Principal (P) = RS 200 /-
• Time period (T) = 2 years
• Rate of interest (R) = 10 % p.a.

To find

• Compound interest (C.I)

Solution

Amount = P(1 + R/100)ᵀ

• 200(1 + 10/100)²
• 200(110/100 × 110/100)
• 200(1.1 × 1.1)
• 200(1.21)
• 242

∴ Compound interest = Amount - Principle

• 242 - 200
• RS 42 /-

Answer 2

Principal(p) = ₹200

Rate(r) = 10%

Time(t) = 2 years

$amount = p(1 + \frac{r}{100}) {}^{t} \\ \\ = 200(1 + \frac{10}{100} ) {}^{2} \\ \\ = 200( \frac{11}{10} ) {}^{2} \\ \\ = 200 \times \frac{11}{10} \times \frac{11}{10} \\ \\ = 242$

Compound interest = amount - principal

= 242-200=42