the compound interest of ₹16000 for 4 years @18% pa is more than the simple interest on same amount for 4 years@8% pa by ₹
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What will be the compound interest be on ` 16000 for 1 and a half years at the rate of 10% per annum compounded half-yearly?
I=P[(1+R%n)nt−1]
Data:P- Principal, R%- Rate of Interest-10%, n-frequency of compounding in a year-2, t- number of years-1.5 years.
I=16000[(1+10%2)2×1.5−1]
I=16000[(1.05)3−1]
I=16000[1.1576−1]
I=16000×0.1576
I=2522
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