the compound interest of rupees 1000 in 2 years at the rate of 10% per annum is
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Answered by
2
Answer:
CI=210
Step-by-step explanation:
A=P(R/100+1)^N
A=1000(10/100+1)^2
A=1000*11/10*11/10
A=1210
CI=A-P
CI=1210-1000
CI=210
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Answered by
1
Amount =x
p = 1000
Time= 2
R= 10% per annum
a=p×(1+r÷100)× t
a=1000×(1+10÷100)×2
a=1000×(110÷100)2
a=1000×11×11÷10÷10
a=1210
ci=a - p
ci =1210 -1000
ci=210
p = 1000
Time= 2
R= 10% per annum
a=p×(1+r÷100)× t
a=1000×(1+10÷100)×2
a=1000×(110÷100)2
a=1000×11×11÷10÷10
a=1210
ci=a - p
ci =1210 -1000
ci=210
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