Math, asked by Alize, 1 year ago

the compound interest of rupees 1000 in 2 years at the rate of 10% per annum is

Answers

Answered by vedasawa55
2

Answer:

CI=210


Step-by-step explanation:

A=P(R/100+1)^N

A=1000(10/100+1)^2

A=1000*11/10*11/10

A=1210


CI=A-P

CI=1210-1000

CI=210


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Answered by feelalive31
1
Amount =x
p = 1000
Time= 2
R= 10% per annum

a=p×(1+r÷100)× t

a=1000×(1+10÷100)×2
a=1000×(110÷100)2
a=1000×11×11÷10÷10
a=1210

ci=a - p
ci =1210 -1000
ci=210
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