The compound interest on $1000 at 10% p.a. compound annually for 2 years is
(a) $190
(b) $200
(c) $210
(d) $1210
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Answer:
(c) $210
Step-by-step explanation:
it is given that principal , P = $1000
rate of interest , r = 10% per annum
time duration, n = 2 yrs
using formula, C.I = P[(1 + r/100)ⁿ - 1]
= 1000[(1 + 10/100)² - 1]
= 1000[(1 + 1/10)² - 1]
= 1000[(1 + 0.1)² - 1]
= 1000[(1.1)² - 1]
= 1000[1.21 - 1]
= 1000 × 0.21
= $210
hence, compound interest = $210
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