Question

the compound interest on ₹10000 at 10% pa for 3 years compounded annually​

Answer 1

Answer:

13,310 - amount compounded

Step-by-step explanation:

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Answer 2

Solution :

$\underline{\bf{Given\::}}}}$

• Principal, (P) = Rs.10000
• Rate, (R) = 10% p.a
• Time, (T) = 3 years

$\underline{\bf{Explanation\::}}}}$

Using formula of the compounded annually :

$\boxed{\bf{Amount=Principal\bigg(1+\frac{R}{100} \bigg)^{2}}}$

A/q

$\longrightarrow\sf{A=10000\bigg(1+\cancel{\dfrac{10}{100}} \bigg)^{3}}\\\\\\\longrightarrow\sf{A=10000\bigg(1+\dfrac{1}{10} \bigg)^{3}}\\\\\\\longrightarrow\sf{A=10000\bigg(\dfrac{10+1}{10} \bigg)^{3}}\\\\\\\longrightarrow\sf{A=10000\bigg(\dfrac{11}{10} \bigg)^{3}}\\\\\\\longrightarrow\sf{A=10000\times \dfrac{11}{10} \times \dfrac{11}{10} \times \dfrac{11}{10} }\\\\\\\longrightarrow\sf{A=\dfrac{10\cancel{000} \times 11\times 11\times 11}{\cancel{1000} }}$

$\longrightarrow\sf{A=Rs.(10\times 11\times 11\times 11)}\\\\\longrightarrow\bf{A=Rs.13310}$

Now;

As we know that compound Interest;

$\longrightarrow\sf{C.I.=Amount-Principal}\\\\\longrightarrow\sf{C.I. = Rs.13310 - Rs.10000}\\\\\longrightarrow\bf{C.I. = Rs.3310}$

Thus;

The compound Interest will be Rs.3310 .