Question

the compound interest on 10000 at 5% for 3 years is​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Compound\:Interest=1576.25\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given: }} \\ \tt: \implies Principal(p) = 10000 \: rupees \\ \\ \tt: \implies Rate\%(r) = 5\% \\ \\ \tt: \implies Time(t) = 3 \: years \\ \\ \red{ \underline \bold{To \: Find: }}\\ \tt: \implies Compound \: Interest = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt : \implies A = p(1 + \frac{r}{100} )^{t} \\ \\ \tt : \implies A = 10000 \times (1 + \frac{5}{100} )^{2} \\ \\ \tt : \implies A =10000 \times (1 + 0.05)^{3} \\ \\ \tt : \implies A =10000 \times (1.05)^{3} \\ \\ \tt : \implies A =10000 \times 1.157625 \\ \\ \green{\tt : \implies A =11576.25 \: rupees} \\ \\ \bold{For \: Compound \: Interest} \\ \tt : \implies C.I =A - p \\ \\ \tt : \implies C.I = 11576.25 - 10000 \\ \\ \green{\tt : \implies C.I=1576.25 \: rupees}$

Answer 2

$\tt{\orange{\huge{Hello!!! }}} B.Q.$

QUESTION :

the compound interest on 10000 at 5% for 3 years is :

ANSWER :

The comound interest formed is equal to Rs. 1576.25.

SOLUTION : .

$</p><p>\begin{lgathered}\bold{As \: we \: know \: that} \\ \tt : \implies A = p(1 + \frac{r}{100} )^{t} \\ \\ \tt : \implies A = 10000 \times (1 + \frac{5}{100} )^{2} \\ \\ \tt : \implies A =10000 \times (1 + 0.05)^{3} \\ \\ \tt : \implies A =10000 \times (1.05)^{3} \\ \\ \tt : \implies A =10000 \times 1.157625 \\ \\ \orange{\tt : \leadsto A =11576.25 \: rupees} \\ \\ \bold{For \: Compound \: Interest} \\ \tt : \implies C.I =A - p \\ \\ \tt : \implies C.I = 11576.25 - 10000 \\ \\ \purple{\tt : \leadsto C.I=1576.25 \: rupees}\end{lgathered}$