The compound interest on a certain sum for 2 yearsat 10% per annum isrs. 525 . the simple interest on the same sum for double the time at half the rate percent per annum is :
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Let the sum be ₹ P.
Given:
R(rate) = 10%, n(time) = 2years
Compound interest (C.I) = ₹525
C.I = [ P (1+ R/100)^n -P]
C.I = P [ 1+ R/100)^n -1]
C.I = P [( 1+ 10/100)² -1
525= P [( 11/10)² - 1 ]
525= P [ 121/100 - 1]
525= P [ (121- 100)/100]
525= P [ 21/100]
P= (525× 100) / 21
P= ₹2500
Sum= ₹ 2500
We know that
S.I =( P× R×T)/100
A.T.Q
Here, P= 2500, R= 5%, T= 4years
S.I = (2500× 5× 4)/100
S.I= ₹ 500
Hence, the simple interest (S.I) = ₹ 500
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Hope this will help you.....
Given:
R(rate) = 10%, n(time) = 2years
Compound interest (C.I) = ₹525
C.I = [ P (1+ R/100)^n -P]
C.I = P [ 1+ R/100)^n -1]
C.I = P [( 1+ 10/100)² -1
525= P [( 11/10)² - 1 ]
525= P [ 121/100 - 1]
525= P [ (121- 100)/100]
525= P [ 21/100]
P= (525× 100) / 21
P= ₹2500
Sum= ₹ 2500
We know that
S.I =( P× R×T)/100
A.T.Q
Here, P= 2500, R= 5%, T= 4years
S.I = (2500× 5× 4)/100
S.I= ₹ 500
Hence, the simple interest (S.I) = ₹ 500
================================================================
Hope this will help you.....
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