Question

The compound interest on Rs. 1000 for 2 years at the rate of 10% per annum is ​

Answer 1

Answer:

Rs.210

Step-by-step explanation:

Principal (P) = Rs.1000

Rate (R) = 10% per annum

Time (n) = 2 years

Amount (A) = P (1 + R/100)ⁿ

=> A = 1000 (1 + 10/100)²

=> A = 1000 (11/10) (11/10)

=> A = Rs.1210

Compound Interest = A-P = Rs.(1210-1000) = Rs.210

Answer 2

ANSWER:

Here, Principal P = Rs. 1000 

R =10% per annum and n=2 years

∴ Amount after 2 years = P (1+200R)2n

= Rs. 1000×(1+20010)2×2=Rs.1000×(1+201)4=Rs.1000×(2021)4

= Rs.1000×2021×2021×2021×2021=Rs.1215.50 

Hence, compound interest = Amount - Principal

=Rs.1215.50−Rs.1000=Rs.215.50

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