The compound interest on Rs1000 at 10% per annum for two years is
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Answer:
amount= rs 1210
interest = rs 210
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First we will write,
Principal= ₹1000
Rate of interest= 10%
Time (n)= 2 years
Now,
We will use the formula
A=P(1+R/100)^n
After putting values
We have,
1000(1+10/100)^2
=1000(1+1/10)^2
=1000x11/10x11/10
=121x10
=1210
Therefore,
Compound interest
= A-P
=₹(1210-1000)
=₹210
Principal= ₹1000
Rate of interest= 10%
Time (n)= 2 years
Now,
We will use the formula
A=P(1+R/100)^n
After putting values
We have,
1000(1+10/100)^2
=1000(1+1/10)^2
=1000x11/10x11/10
=121x10
=1210
Therefore,
Compound interest
= A-P
=₹(1210-1000)
=₹210
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