Question

the compound interest on rupees 15625 for one and half years at 8% per annum compounded half yearly is​

Answer 1

Given :-

• Principal = P = Rs.15625
• Time = T = 1(1/2) year = (3/2) years.
• Rate = R = 8% compounded half yearly.

To Find :-

• Compound interest = CI = ?

Solution :-

we know that, when rate is compounded half yearly,

• Rate = Half of given rate .
• Time = Double .

so,

• P = Rs.15625
• T = (3/2) * 2 = 3 years.
• R = 8/2 = 4% compounded yearly .

now, we know that,

• CI = P[{1 + (R/100)}^T - 1]

putting all values we get,

→ CI = 15625[{1 + (4/100)}³ - 1]

→ CI = 15625[{1 + (1/25)}³ - 1]

→ CI = 15625[(26/25)³ - 1]

→ CI = 15625[(17576/15625) - 1]

→ CI = 15625 * {(17576 - 15625)/15625}

→ CI = (15625 * 1951)/15625

→ CI = Rs.1951 (Ans.)

Learn more :-

CI in 2yr is Rs. 1600 and in 3 yrs it will be Rs. 1700. Find the rate of interest.

https://brainly.in/question/32463301

Answer 2

Answer:

rupees 1951

Step-by-step explanation:

given

p= rs 15625

rate per annum=8% since half yearly, 8% / 2 = 4%

n ( years) = one and a half years = 3 half times

first, A = $p*1+r/100 power 3$

           = 15625{ 1 + 4/100} power 3

            15625 { 104/100} power 3      BY GETTING LCM

             = 15625 { 26/25 * 26/25 * 26/25}

              =15625 { 17576/15625}

               A = 17576

              CI = A-P

               CI = 17576-15625

                 CI = Rs 1951