Question

The compound intetest on rs 1000 at 10% per annum for 2 years is

Answer 1

the compund interest is 200

Answer 2

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Rs 210

Step-by-step explanation:

Principal(p) = 1000

Rate of interest (r) = 10%

Time(t) = 2 yr

Amount(a) = p(1+r/100)^t

$1000 { (1 + \frac{10}{100} )}^{2} \\ \\ 1000 {( \frac{110}{100} )}^{2} \\ \\ 1000 \times \frac{11}{10} \times \frac{11}{10} \\ \\ 10 \times 121 \\ \\ 1210$

Compound Interest = a - p = rs (1210 - 1000)

= Rs 210