Question

The compound na2co3.Xh2o has 50%h2o by mass. The value of x?

Answer 1

Answer: 3

Explanation:

Weight of na2co3 is 106. Has 50 % h20.

So total mass of h2o= 106/2=53

Weight of 1 molecule of h2o= 17.5

so,no. of molecules =53/18=3 (approximately)

So no of molecules of water is 3.

X=3

Answer 2

The value of x is 6.

Explanation:

$Na_2CO_3.xH_2O\rightarrow Na_2CO_3+xH_2O$

Molar mass of $Na_2CO_3$ = 106 g/mol

According to stoichiometry:

(106+18x) g of $Na_2CO_3.xH_2O$ decomposes to give 18x g of $H_2O$

As given :

$\frac{18x}{106+18x}\times 100=50$

$x=6$

Thus the compound $Na_2CO_3.xH_2O$ has value x = 6

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