The compound ratio of 3:4 and the inverse ratio of 4:5 is 45:x Find x
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If the compound ratio of 5 : 8 and 3 : 7 is 45 : x. Find the value of x.
Compound ratio of 5:8 and 3:7 = 5/8 ? - 3/7 = 15/56.
Now product of extremes = Product of means => 15:56 :: 45:x => 15x = 2520 => 2520/15 = 168.
x = 168.
thanks ,;)
Compound ratio of 5:8 and 3:7 = 5/8 ? - 3/7 = 15/56.
Now product of extremes = Product of means => 15:56 :: 45:x => 15x = 2520 => 2520/15 = 168.
x = 168.
thanks ,;)
Answered by
4
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___________________________________________________________
→ Here is ur questions answer:
√ Given ratios are:
(i) ⇔ 3:4
(ii) ⇔ inverse ratio of 4:5 is 5:4
⇒ 3 multiply 4: 4 multiply 5 = 45:x
12: 20 = 45:x
12/20=45/x
45 multiply 20/12=x
45 multiply 5/3 =x
15 multiply 5= x
∴ then , x=75
___________________________________________________________
★★★i hope this may help u!!★★★
___________________________________________________________
→ Here is ur questions answer:
√ Given ratios are:
(i) ⇔ 3:4
(ii) ⇔ inverse ratio of 4:5 is 5:4
⇒ 3 multiply 4: 4 multiply 5 = 45:x
12: 20 = 45:x
12/20=45/x
45 multiply 20/12=x
45 multiply 5/3 =x
15 multiply 5= x
∴ then , x=75
___________________________________________________________
★★★i hope this may help u!!★★★
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