Question

The compound that provides a carboxylic acid, upon treatment with br2 / naoh followed by acidification, is.

Answer 1

Explanation:

The haloform reaction is a chemical reaction where a haloform (CHX3, where X is a halogen) is produced by the exhaustive halogenation of a methyl ketone (RCOCH3, where R can be either a hydrogen atom, an alkyl or an aryl group), in the presence of a base.[1][2][3] The reaction can be used to transform acetyl groups into carboxyl groups or to produce chloroform (CHCl3), bromoform (CHBr3), or iodoform (CHI3).

Answer 2

only methyl ketones can produce carboxylic acid  upon treatment with Br2 NaOH followed by acidification .

Explanation:

The reaction is known as haloform reaction .

The following steps takes place which conversion :

1. –CH3 on a methyl ketone is converted to a trihalomethyl group.
2. This decent leaving group allows the carbonyl to undergo a nucleophilic acyl substitution reaction with the NaOH already present in the reaction.
3. loss of proton as carboxylic group is acidic ,
4. acidification will stablize  carboxylate ion to carboxylic acid .

To summarize alpha-halogenation is used to convert  a methyl ketone into carboxylic acid .